A woman of mass 90 kg stands upright on a tile floor. If the area of contact of her shoes and floor is 300 cm^2,...

      

A woman of mass 90 kg stands upright on a tile floor. If the area of contact of her shoes and floor is 300 cm^2, determine the average pressure she exerts on the floor. (Take g=10 N kg^-1)

  

Answers


joseph
Nb. Pressure = force/area
Force = pressure x area
=90 x 10
=900N
Area = 300 cm^2
=300/10000 m^2
=0.03m^2
Thus pressure = 900/0.03 Nm^-2
=30000Nm^-2
joseph rimiru answered the question on October 18, 2017 at 17:39


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